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Komposisi Fungsi Part 1 - Operasi Aljabar Pada Fungsi [ Matematika Wajib Kelas X ]

18:04EnglishTranscribed Jul 24, 2026
0:00

Hi assalamualaikum warohmatullohi

0:01

wabarokatuh meet me again with Deni

0:04

Handayani on the metlife channel in

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this video we will learn the material of

0:08

function composition and this is the first part of the video

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there are three sub materials that

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we will learn in this first part of the video

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including the first

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algebraic operations on functions including addition subtraction

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multiplication and

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division operations Sumatra second we will

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learn about the properties of

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algebraic operations on functions and Sumatra

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third we will learn how to

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determine the domain of the results of algebraic operations of

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several functions Okay a person

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Let's just discuss the material

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clap

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[Music]

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Okay now we will learn the material of

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algebraic operations on functions actually

0:59

this is the material that friends have

1:01

learned in grade 8 of junior high school but consider

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this to refresh your memory because

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we will use this material in the

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next Sumatra Okay Let's just discuss

1:12

for example there are two functions including

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function f and function G then the

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following algebraic properties apply

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first for addition if

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friends find a form like this

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F + GX that means it is the same as f x

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plus GX Then for subtraction F

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Min GX it is the same as f x minus

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GX likewise for multiplication F * GX

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is = FX * GX see the writing and

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also with the division F divided by GX

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is the same as fx divided by GX no for

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division there are conditions yes remember for

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division it cannot be divided by

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zero while here the gps is

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as a divisor then GX is not Hi can be

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zero so that this is defined

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because we discuss the example of the problem for

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example given three functions fx GX and

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hx like this yes we will find the

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first F plus GX then F minus

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GX then the third G * hx and the

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4th G divided by kxk we Answer the first

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First for F plus GX this is the same

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as fx plus GX friends

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pay attention to the fx function the fx function is 3

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x to the power of 3 min 2 x squared + 4 X min 5

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so the effect we replace with this

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friends so 3x to the power of 3 min 2 x

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squared plus four X min 5 then

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add GX pay attention to the GX GX function this one is

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x squared min 5 x + 6 we

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write x squared min 5 x plus six

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next friends

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just add it up Hi and remember to

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add algebraic forms friends

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can only add the

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same powers that are the same degree Here the

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cube power is no longer there so the

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cube power we rewrite

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then the ^ 2x squared here

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there are two namely min 2 x squared and x

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squared we add see the

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coefficient is this coefficient is

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negative two here positive 1 min 2 plus

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one that is bin1 so here min 1x

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squared or written min x squared

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then the variable x here there are two

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namely 4x and mi5x directly so

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add 4 plus negative 5/4

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minus 5 how much is negative 1 Bro so

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negative 1x or negative X then

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the constant or the number is negative 5 and 6

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mi5 + 6 how much is positive one so plus 1

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well this is the result of the addition is

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easy right friends can only

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add terms that are the

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same degree or the same power

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then for subtraction number 2f

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minus GX is the same as f x

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minus GX the method is the same as FX which we

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rewrite yes FX is this one 3x to

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the power of 3 min 2 x squared 4 X min 5 we

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rewrite then subtract it

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as a note for subtraction

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make sure friends Give brackets

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different from addition not given

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forums problem yes to subtract

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make sure friends Give brackets

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yeah minus GX GX that is x squared

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min 5 x + 6 in brackets okay

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now we open the brackets

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here we rewrite then

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this is negative times positive negative times Positive

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that is negative so negative x

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squared negative times negative it becomes

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positive so here it becomes plus 5x negative

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times positive negative now min 6 clear yes

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Now we add the

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same degree that has the same power

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as before here the third power is no

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longer there so we rewrite 3x ^ 3

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which is SWT here where min 2 x squared

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and this is min x squared negative 2

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minus one negative 3 so negative 3

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x squared then the X only 4x and 5x

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4 x + 5 x9x then negative 5 minus

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6 negative 11 and this is the result of

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my subtraction so the difference for

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addition friends is no problem

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No Give brackets but for

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subtraction make sure Give brackets

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Okay now we discuss the third

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multiplication for multiplication GK cleverly =

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GX times hxd.exe it is x squared minus

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5 x + 6 then times the right x minus

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two Now the way to switch it friends

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multiply one by one yes Hi x squared

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multiply by snack and X ^ 1 if

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multiplied by the power it is added JD x ^

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2 * x ^ 1 means x to the power of 2 plus

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one x ^ 3 remember the power is added

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then x squared times negative duet

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becomes negative 2 x squared then

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this one

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Min 5 x times x this is the power of -1 this ^ 1

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batia Next becomes the power of 2 which is not

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Min 5 x times x min 5 x power of 2

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then Min 5 x * min 2 negative times

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negative is positive so plus 10x

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then this is six times x6x then six

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times negative 2 negative

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12 next we Simplify we

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operate the same power here the

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power of three is no longer there yes we

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write again x ^ 3 which is the power of 2 here

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there are two friends min 2 x squared

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minus 5 mint container two minus

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5 How much is min 7 so min 7 x squared

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then the variable X here is 10 x

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+ 6 x how much is 16x then minus 12

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Okay now we discuss the fourth

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division question y divided by hx this is the same

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meaning as GX divided by hx GX is x

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squared min 5 x + 6 and the result is

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X min 2 Now for division if

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this can be factored friends

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factor it x squared min 5 x + 6

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we factor it into X min 2 B min

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3 Now for those who are still confused about how

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to factor it I have

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discussed the video later the link will be included

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in the description of this video Eh how to

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factor the quadratic form so if

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I discuss it again here it seems

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too long now friends pay

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attention between the numerator and denominator

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there are the same or not X min 2 B

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min two we just cross it out so the answer

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is a Hi min 3 with the note that the

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divisor cannot be zero so hx

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cannot be zero while

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zekhan X min 2 X min 2 is not equal to

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zero meaning X not equal to zero

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plus 2x is not equal to two this is

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the condition Well that's how to do

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algebraic operations on functions including addition subtraction

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multiplication and

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division yes that simple now

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we discuss eh next moment namely the

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properties of algebraic operations on functions

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there are four properties the first for

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addition is commutative

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meaning if friends find F

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plus GS it can be reversed to g-plus

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FX so for addition it is

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commutative meaning the order can be

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swapped okay Then the

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second associative property in addition

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well in addition besides commutative is

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also associative for example there are

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three

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c & f plus getplus X that friends

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can do efxplus Bank of Tokyo

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can also g-plus first freely because this is

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associative then the third besides addition multiplication is

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also the same it

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is commutative yes commutative property

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in multiplication FK Lights the value will be the

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same as gkfx so the order will be

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reversed the result will be the same then

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the fourth multiplication is also

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associative FK liege times hx Friends

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can do FKG first or can

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also do GK see first the results will be the same

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Well these are the properties of algebraic operations

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on the function now we discuss the

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last material in this video,

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namely the domain of the function of the result of

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algebraic operations of several functions first

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for the domain of the result of the addition for example

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friends will find the domain of the addition of

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function f and function G the domain

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of the result of the addition of F with G is the

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intersection of function f with the domain of

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function G so friends must be able to

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find the domain of the function first eh

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for example for example it is known that the function fx

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= 3 x squared and the function gx is

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the root of x + 5 Determine the domain of the domain

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the domain is the same as the domain yes the

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domain of the function f plus GX

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first friends find the domain

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of the function fx the function fx is 3 x squared

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here are there any exceptions or not If x

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squared it can invite nxc whatever it is, it doesn't

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matter so the domain of the function f is all

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real numbers X Bima X members of

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real numbers Then for GX GX = root x + 5

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Well for the roots there are conditions

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friends the contents in the roots

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cannot be negative yes so here the domain is

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filled in so that it cannot be negative

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meaning the contents in The root must be

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more than or equal to zero so x +

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5 is more than 10 then x is more than or

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equal to zero minus 5 negative 5

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then the domain of gfxdomain G is

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x where x is more than = negative 5 and X is a

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real number member well this is the domain

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of the function G remember if the function

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is a root then the domain inside the

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root cannot be negative or must be

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more than or equal to zero Well now

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we look for the intersection friends we

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make a number line so friends

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can see the first illustration the

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domain of f here is all X where x is a

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real number member weight in all the

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numbers on this number line

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that is the domain of the function f Well

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now the domain of the function g x is more than =

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negative 5 negative helps which This

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means from here more than that means

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to the right Gan teh negative 5 to the right well the

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intersection is the area that is shaded

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by both make sure the area here

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friends yet i come here then

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the intersection domain of efxplus G is x

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where x is more than = negative 5 and X is a

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real number member

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Okay now we continue How to

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determine the domain of the subtraction result

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for example there is a subtraction of the function f

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minus G then the domain of the

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subtraction result is a slice of the domain

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F and the domain is not so the method is the same

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we take the slice for example

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if it is known that the function fx is three

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over x + 2 and GX = root x minus three

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Determine the origin of the region when

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the domain of f minus GX the method is the same

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we first find the domain of the effect function FX is

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3 over x plus two Well if the

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root form is the condition inside

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so that it cannot be negative Well if

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friends find a division or

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rational form like this the condition is the

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divisor or the one in Mbak or the

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denominator must not be zero

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Why because if it is divided by zero it is not

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defined yes so here the condition is the

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denominator or x + 2 is not 0

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then X is not 0 minus two is

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not negative 2 or X is not =

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negative 2 well this is the domain of the function f

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so the domain of the function F is x where x is

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not = negative 2 and X is a member of

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real numbers Now for the function GX GX is

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= root x min 3 this is the root form remember

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the condition inside the root cannot be

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negative so X min 3 must be

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more than or equal to zero then X is more

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than or equal to zero plus 3 x is more

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than = 3 then the domain of G is x where x

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more than = 3 x members of real numbers

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Now we make the number line

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to determine the first intersection

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X is not = negative 2 negative two

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here is not equal to negative 2 so

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we circle this so it doesn't go

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into your friends' answers then X more

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than = 3 from 3 to the right well coincidentally

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negative two which is not allowed is already

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outside the answer so the answer is

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yes, this one friends so the

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answer is the domain of FB konige is

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x where x more than = 3 and X members of

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real numbers Okay now we continue

14:29

How to determine the domain of the

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multiplication result for example your list of functions

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f and function G then the domain is the

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same method is the intersection of the two functions

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intersection of the domains of the two functions

14:42

Example

14:45

Hi if it is known that the effect is 3 x

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squared and GSC is 1 per X min 4

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Determine the domain of f * GX yes

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the method is the same we find the domain of f and the

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domain of G then we slice the

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domain of f this quadratic form there

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are no conditions so x

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is all members of real numbers

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while for gx1 per X min 4 because

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this is a rational form remember the divisor

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cannot be zero so X min 4 is not

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worth 0 then X is not worth zero

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plus 4 is not worth 4 then the domain of G

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is x is not = negative 4 we make a

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number line the domain of F is all

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real numbers so we shade everything

15:29

then the domain is not worth 4

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so here it cannot be worth 4 yes so like

15:36

this it doesn't enter friends then the

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answer is the domain of FK Lights is

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all real numbers except four so X is

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not with four X members of

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real numbers like this Okay we basesumatary

15:50

last is the domain of the division result

15:54

For example there is a division of F divided by ge then the

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domain of frg is the domain of F

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intersected with the domain of G well intersected

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again with the condition friends because

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here the division remember the divisor

16:08

cannot be worth zero this is the condition of the divisor

16:11

cannot be worth zero because the design of

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the divisor is G style so GX is not

16:15

worth not Okay for example

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if it is known that FX = 3 x squared and GX =

16:23

X min 3 Determine the origin of Ever

16:26

GX yes the domain of the effect is all members of

16:30

real numbers then GX is

16:33

x-men 3 yes here there are any conditions

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because this is not a fraction

16:39

and also not a root form so the domain

16:42

of g Those are all real numbers too

16:45

then we just use the condition because

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we will look for the division of F divided by ge

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three this will be as a divisor

16:53

the divisor must not be zero so GX is

16:55

not zero this is the condition gxl

16:59

badge situ X min 3 x min 3 is not equal

17:02

to zero then X is not = 3 we make

17:05

our number line the third intersection the

17:09

third condition Nia when this domain

17:11

we English

17:13

the first DF domain F is all

17:17

members of real numbers means we shade

17:19

all Then DG is also the same all

17:21

members of real numbers so we

17:23

also shade all then the condition Mbak X

17:26

is not = 3 so in this art section it

17:28

cannot be as an answer does not

17:31

meet yes this does not meet then

17:33

the answer is all real numbers

17:37

except three domains never g = x where x

17:42

is x is not = 3 and X is a drill member

17:45

so the exception is x = 3 Apart from

17:48

that, you can Okay, that's all for

17:51

this video, I apologize if there are any shortcomings,

17:53

I hope this video can be useful for

17:55

friends who are studying mathematics, I am

17:58

Deni Handayani, I resign

17:59

Assalamualaikum

18:00

warohmatullohi wabarokatuh hi hi hi hi

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