Full Transcript

·YouTLDR

F338-Hukum 2 termodinamika ,perumusan Kelvin-Planck ,Clausius dan entropi

14:17EnglishTranscribed Jul 28, 2026
0:00

Hello hello

0:02

fans and physics lovers

0:05

this time I will explain about the

0:06

2nd law of thermodynamics

0:11

The first 2nd law of thermodynamics formulated by

0:14

Kelvin-Planck is about combustion engines it is

0:17

impossible to make an engine that draws

0:20

heat from high tendons and converts it

0:22

all into mechanical work So

0:25

if for example Here you have a

0:28

hot reservoir for example for a gasoline engine when it is

0:31

burned it will produce heat right Well

0:33

if this is all converted

0:36

into mechanical work it is impossible that

0:39

if it is possible like this wow this

0:43

can be perfectly economical Your engine so buy

0:46

1 liter of gasoline it is all burned into heat

0:50

all into mechanical work Well that is

0:53

very impossible yes Hi well

0:55

this is what is meant by

0:58

the laws of the thermometer the Kelvin-Planck formula

1:01

well what happens in nature is like

1:04

this a real engine is like this it

1:07

burns gasoline usually a combustion engine

1:10

here burns gasoline the calories that appear are

1:13

not all converted into

1:16

mechanical work some are also thrown out through the

1:18

exhaust

1:20

Is there a motorbike car that does not

1:24

have an exhaust it must have an exhaust

1:26

because the heat that is taken the heat that is

1:29

taken is not all Duba becomes

1:33

mechanical work but some are thrown out

1:35

through the exhaust that is the clear engine in

1:39

this world like this Well the second one is

1:42

Clausius's formula so the

1:44

thermohygrometer laws by Clausius are

1:47

about the cooling machine, it is impossible to

1:50

flow heat from low temperature to

1:52

high temperature without external effort

1:55

Hi so for example here there is a responsibility to

1:57

shoot this year this low element has a

1:59

high temperature which contains low calories

2:02

it must flow from high temperature to

2:04

lower temperature It cannot be

2:07

reversed from low to high

2:09

for example the temperature in your room is

2:13

successful Brazzers then the door is opened

2:16

it must be

2:18

hot air flowing from

2:22

your environment to the room and it cannot be reversed

2:25

like that so the heat flow is

2:28

naturally spontaneous from high temperature to

2:31

lower temperature for sure

2:34

hi why what if we for example

2:36

want to flow heat from low temperature

2:39

to high temperature it is possible but it must be

2:43

with external effort well this is what

2:46

was said earlier yes it is impossible to

2:47

flow heat from low temperature to

2:49

high temperature without me realizing outside Well

2:51

if there is external effort you can

2:54

flow heat from the lowest reservoir

2:58

to Syria higher for example this

3:00

is how a real cooling machine works

3:03

so a cooling machine for example AC

3:07

draws heat from inside the

3:10

cooled room to its environment which has a

3:13

higher temperature but that is with

3:15

electrical effort yes So if you have an

3:18

AC that is not plugged in,

3:21

you will not turn on the

3:23

electricity, it

3:25

will not cool your room, there is no heat

3:28

drained, the family temperature is

3:31

higher like that

3:33

Hi Well now 02.00 thermodynamics the

3:37

third formulation is about entropy

3:40

Nahin trophy the universe always increases

3:43

in an irreversible process and

3:45

there is always a Princess Belle process

3:48

Hi Well later I will explain what the

3:50

irreversible and reversible processes

3:53

Nahin trophy that I explained first what

3:56

is the intro Pi entropy is a measure of the

4:00

amount of heat energy that cannot be

4:02

converted into work for example in a

4:05

piston engine it will rub against

4:06

the cylinder Well if it rubs it

4:09

produces heat how much of the necklace

4:11

can be converted into work, it cannot,

4:14

instead the heat that appears is detrimental to the

4:16

work so the engine's work will be

4:20

reduced like that Because there is something that

4:22

turns into heat like that

4:25

Hi well then secondly there are

4:27

also those who define intropia

4:29

as the level of the system's energy state

4:33

the more energy it has, the

4:37

greater the entropy for example you

4:40

imagine there is a metal the

4:43

left end is very hot the right end is

4:47

very cold if the left end is very

4:50

hot while the right end is

4:52

very cold Well that means the energy is

4:56

localized like that from the heat

5:01

on the left The cold on the right Well that is

5:04

said to be not random energy but

5:07

over time it flows to Hi Sis Nur

5:10

flowing from the hot end to the

5:12

cold end finally the heat is evenly distributed if

5:15

the heat is evenly distributed it is said to be

5:18

random energy meaning the instructions are increasing like that

5:23

Well entropy can also be said

5:26

to be the level of disorder of the system

5:29

for example imagine there is a room filled with

5:35

30 students, the

5:38

students are studying comfortably,

5:40

suddenly the room is burned, what

5:43

happens then all the students will definitely run

5:48

helter-skelter the system is in a

5:50

more chaotic state like that

5:53

Sis maybe it is getting calmer when there is a

5:56

fire Wow never mind, yes, death is made by

5:58

that experience is impossible,

6:01

the students will definitely all spray out Well

6:04

that means the system is said to be

6:07

disordered and assume the students were

6:09

gas particles, yes, of course the refrigerator if

6:12

heated is also like that more

6:14

Wrong Behavior the system is said to be

6:17

increasingly disordered if it is increasingly

6:20

disordered then it is said that the entropy

6:23

increases like that Well if at a constant temperature the

6:27

entropy change that occurs

6:29

is delta Cipete how is Delta the

6:33

heat change that occurs while

6:35

teto is the temperature

6:37

well Delta es the entropy change is

6:41

always 0ad meaning

6:43

entropy The universe is always right

6:46

on the reversible process,

6:50

the reversible process is a process that can Bale

6:52

means the process can be returned

6:55

so that the

6:57

thermodynamic components

7:00

related to pressure, volume, temperature

7:02

can really be returned

7:05

to their original state

7:08

Hi, the reversible process is usually a

7:11

very slow process or a

7:14

quasistatic process,

7:17

so the quasistatic process means

7:20

the process that takes place at

7:21

any time can be said between the system

7:25

and its environment is in a state of

7:27

equilibrium.

7:29

This means that for example the temperature of the system

7:32

with distilled water is

7:36

very small, approaching North, as well as

7:39

the volume, pressure, and

7:42

so on, so the thermodynamic components

7:45

between the system and the environment are

7:49

the difference approaching Noor

7:52

Hi, the reversible process, for example,

7:55

is the Karno cycle process. Well, later

8:00

I will give an example of it, the process

8:05

in nature is of course naturally an

8:07

irreversible process, an irreversible process

8:11

is a process that cannot be returned

8:14

to its original state, cannot be reversed, well,

8:18

this will definitely cause an increase in

8:21

the entropy of the universe So the Delta es

8:25

will be greater than zero,

8:29

for example, you know, heat and heat is

8:31

always from what, from a high temperature to a

8:35

low temperature So if for example

8:37

you open the door of your room air-conditioned,

8:39

the heat must flow from

8:41

your environment to your room, right?

8:45

Hi Well, that's an irfal process, annoying

8:50

Hi and it can't be used, bro, it

8:52

can't be reversed, so for example, 6 back

8:55

from the heat flowing from your room

8:58

naturally out, that's impossible,

9:00

so in an irreversible process, the

9:03

entropy always increases, like only the

9:07

times, it also continues to increase, right, it ca

9:11

n't be reduced, for example, your age

9:13

continues to increase. It can decrease,

9:15

but I, so your age always increases, the

9:18

years always increase, finished in 2002,

9:22

2001, 2002, and the fun part is like that, right? Well,

9:25

like your age can divide 1920 and

9:28

so on, right? So, because

9:31

in an irreversible process, the instruction

9:35

always increases, the intropia of the universe

9:38

always increases, so it's said that

9:40

entropy is an arrow of time or

9:43

time error

9:47

Hi Well, I've explained this, right? The

9:49

Delta of the istir won't change.

9:51

Another tropical one is joule per Kelvin

9:53

and again, the change in heat in the

9:55

gas system, the unit is Jul, the change

9:58

is Suga, the unit is Kelvin

10:01

Hi Well, introverted with sub rubah, it

10:04

can also happen, so the Delta of the istir is the

10:06

change The entropy can be formulated as MJ

10:09

lonte2 one box or you can use the

10:12

molar heat capacity of the gas, namely Delta

10:16

snc lonte2 or this one I have already

10:19

explained Delta es still states

10:21

the change in entropy m is the mass Unit

10:24

kg is the specific heat of the gas Jere he is large

10:27

molar heat capacity of the gas daily one

10:30

only has mall T1 swagga while T2

10:33

is a gas end

10:36

Hi watch more clearly I will

10:38

give examples of questions example questions one by one

10:40

how much is the change in entropy of the gas system

10:42

in one cycle In the Kaho cycle, so it

10:46

becomes like this, it means

10:48

my intention is to have a PV diagram of the Karno cycle, it

10:51

is a cycle that is limited by two

10:53

isothermal processes and 2 adiabatic processes

10:57

or b is an isothermal expansion process,

10:59

heat enters the system,

11:02

for example Q1, well this is a

11:05

real shooting from a to b so later T1 is

11:08

greater than T2, you

11:11

can imagine At that time the temperature in the

11:13

engine is right, burn gasoline in the engine,

11:15

for example T2 is the temperature around the

11:18

exhaust Well if it works, it is a

11:21

shallow adiabatic expansion process, the jacket

11:24

is an isothermal compression process,

11:26

compression because it occurs volume decrease

11:29

yes if expansion occurs

11:31

volume increase well T2 is the low temperature

11:34

here in the impression process technical issue

11:38

heat will be removed from the gas system if

11:42

D in that direction is the compression process there is a

11:45

babis in the adiabatic process there is no

11:49

heat exchanged between the system

11:51

and the environment so Delta giginya is zero

11:54

here also Delta kynya is zero okay well in the

11:57

Karno cycle process it applies that the story of the

12:01

one box is equal to q22 If

12:04

you don't understand why this happens

12:06

Look at my previous video which

12:09

discusses the derivation of this formula

12:12

Well if we calculate how much

12:14

entropy change occurs in the

12:16

isothermal expansion process from a to b it

12:19

is the story to party one how much heat

12:22

is entered divided by shooting that is

12:24

this isothermal expansion process Well if in

12:30

this isothermal compression process If it is removed then

12:33

Delta scdd is Minaj 22 Why

12:38

minus because this heat is removed from the

12:41

gas system Well if the total entropy change

12:44

means Delta ESAB plus

12:46

scd data Delta sapi There is another

12:49

one party one Delta sdd is

12:52

wingki2 pete2 but the carnot cycle earlier

12:56

is ideal class yes it is reversible

12:59

Well so if infosebel Q1 box 1 =

13:03

qidu or two then I can replace this

13:06

yes Q2 pete 2 becomes q1pp one well

13:11

if I add the result is

13:13

zero because Delta es now means In

13:16

this Karno cycle there is a process that

13:20

Revo sebel the process can be reversed

13:24

hi okay example of the second question Ghazali

13:27

has a molar heat capacity of 12.5

13:30

joules per mole per Kelvin in a

13:32

constant volume process If

13:34

two moles of helium gas are heated without you buffer

13:37

realizing su-300 Kelvin becomes 500 Kelvin

13:39

calculate the change in entropy Well we

13:42

Answer yes Well the change in entropy

13:45

is ncv lonte2 per

13:48

t1n that is Mal from the suit yes this

13:52

occurs at constant volume so this

13:54

is the molar heat capacity of gas at

13:56

constant volume well

13:58

then we just enter the number the

14:00

moral is two cv 12.5 t2t one

14:05

I enter jebret the result is

14:08

12.7 7 juplret Kelvin this is the change in

14:12

entropy that occurs

More transcripts

Explore other videos transcribed with YouTLDR.

Get the TLDR of any YouTube video

Transcribe, summarize, and repurpose videos in 125+ languages — free, no signup required.

Try YouTLDR Free