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Molecular Orbital Theory Explained in 11 Minutes

11:12EnglishTranscribed Jul 26, 2026
0:00

To understand molecular orbital theory

0:02

deeply, we will cover these topics in

0:04

this video. Main postulates of molecular

0:06

orbital theory, difference between

0:08

bonding molecular orbitals and

0:10

antib-bonding molecular orbitals, what

0:12

is bond order and how we can find it.

0:14

How to check paramagnetic and

0:16

diamagnetic behavior and how to

0:18

determine the energy order of molecular

0:20

orbitals. First, let's start with the

0:22

main postulates of molecular orbital

0:24

theory. The first postulate says that

0:26

atomic orbitals intermix to form

0:28

molecular orbitals. For example, in the

0:31

case of a hydrogen molecule, when its

0:33

two atomic orbitals intermix with each

0:35

other, they result in the formation of

0:36

molecular orbitals. And we will discuss

0:39

this in detail. According to the second

0:41

postulate, the number of molecular

0:42

orbitals formed will always be equal to

0:45

the number of atomic orbitals that

0:46

intermix. This means that if two atomic

0:49

orbitals are involved in mixing, it will

0:51

always form two molecular orbitals.

0:53

According to the third postulate, only

0:55

those atomic orbitals will intermix with

0:57

each other that have comparable

0:58

energies. This means that the 1s orbital

1:01

will overlap with the 1s orbital of

1:03

another atom. And similarly, the 2s

1:05

orbital will overlap with the 2s orbital

1:07

of another atom. It is not possible that

1:09

the 1s orbital of one atom can overlap

1:12

with the 2s orbital of another atom.

1:14

Now, we will move towards bonding

1:16

molecular orbitals and antib-bonding

1:18

molecular orbitals. To understand this,

1:20

we will draw the molecular orbital

1:22

diagram of a hydrogen molecule. As we

1:24

know, a hydrogen atom has one electron

1:27

and it is present in the 1s orbital. So,

1:29

it means that in order to form a bond,

1:31

these atomic orbitals should intermix.

1:34

Here we can see that two atomic orbitals

1:36

are taking part in mixing. So, it means

1:38

that two molecular orbitals will be

1:40

obtained. But we need to keep in mind

1:42

that half of the molecular orbitals will

1:44

have lower energy than the parent atoms

1:45

and half will have higher energy than

1:47

the parent atoms. So it simply means

1:50

that the two molecular orbitals which

1:51

will be formed in this case, one will

1:53

have lower energy and the other one will

1:55

have higher energy than the parent atom.

1:57

Now it's time to see what actually is

1:59

the difference between bonding molecular

2:01

orbitals and antib-bonding molecular

2:03

orbitals. Keep in mind that molecular

2:05

orbitals that have lower energy than

2:07

their parent atomic orbitals will be

2:09

called bonding molecular orbitals and

2:11

those having higher energy than their

2:13

parent atomic orbitals will be

2:14

antib-bonding molecular orbitals. We

2:17

need to understand one more important

2:18

point. Since anti-bonding molecular

2:20

orbitals are higher in energy than

2:22

bonding molecular orbitals, they will be

2:24

denoted by placing a star on them. For

2:26

example, sigma star and pi star. Bonding

2:29

molecular orbitals due to their lower

2:30

energy will be denoted without a star

2:32

and they will be called sigma and pi

2:34

bonds. Now, we need to understand how we

2:36

should place electrons in molecular

2:38

orbitals. Keep in mind we need to follow

2:40

the rules of electronic configuration

2:42

such as Pauliey's exclusion principle,

2:44

offbal principle and Hun's rule. For

2:46

example, in the case of a hydrogen

2:48

molecule since there are a total of two

2:50

electrons in the atomic orbitals of

2:52

hydrogen, we need to place them in

2:54

molecular orbitals. Both electrons will

2:56

be placed in the sigma 1s orbital which

2:59

is actually a bonding molecular orbital

3:00

and no electron will be available for

3:02

antib-bonding molecular orbitals. This

3:04

happens due to the offbell principle

3:06

which states that electrons must be

3:08

filled according to their increasing

3:09

energy levels. So first we need to

3:12

complete the sigma 1s orbital and both

3:14

electrons will be filled in it. Now we

3:16

will discuss what bond order is and how

3:18

we can find it. Actually bond order

3:20

refers to the total number of bonds

3:22

formed between two atoms when their

3:23

atomic orbitals overlap. We can find the

3:25

bond order of any molecule with this

3:27

formula. Bond order is equal to total

3:30

number of electrons in bonding molecular

3:32

orbitals subtracting total number of

3:34

electrons in anti-bonding molecular

3:36

orbitals and divided by two. We can

3:38

understand this with the example of a

3:40

helium molecule. As we know the atomic

3:42

number of helium is 2. So its veence

3:45

electrons will be present in the 1s

3:47

orbital and its electronic configuration

3:49

will be 1 s2. To draw its molecular

3:51

orbital diagram, the 1s orbital of one

3:54

helium atom should intermix with the 1s

3:56

orbital of the other helium atom.

3:58

According to the postulates, two

4:00

molecular orbitals should be formed. One

4:02

will have lower energy than the parent

4:04

atom and will be called a bonding

4:06

molecular orbital while the other will

4:07

have higher energy than the parent atom

4:09

and will be called an anti-bonding

4:11

molecular orbital. As we can see, there

4:13

are a total of four electrons present in

4:15

the atomic orbitals of helium. So now we

4:18

need to place them in molecular

4:19

orbitals. According to the rules, two

4:21

electrons should be placed in the sigma

4:23

1s orbital and two will be placed in the

4:25

sigma star 1s orbital. Now to find the

4:28

bond order, we will apply the formula.

4:30

As we can see, two electrons are present

4:32

in bonding molecular orbitals and two

4:34

electrons are present in anti-bonding

4:36

molecular orbitals. So it will be 2

4:39

subtraction 2 and divided by two and its

4:41

answer will be equal to zero. This means

4:43

that the bond order of helium is zero.

4:46

From this we can conclude that helium

4:48

will never form a bond since its bond

4:50

order is zero. You can also check this

4:52

for a hydrogen molecule and its bond

4:54

order will be one which shows that

4:56

hydrogen will always form one bond. Now

4:58

we will understand the difference

4:59

between paramagnetic and diamagnetic

5:02

behavior. We need to remember that if

5:03

there is any unpaired electron present

5:05

in molecular orbitals then that molecule

5:07

will always be paramagnetic in nature.

5:09

But if all the electrons are paired and

5:11

no unpaired electron is present in

5:13

molecular orbitals then we should say

5:15

that it is diamagnetic in nature. To

5:17

understand this deeply and also to

5:19

understand the main concepts of

5:20

molecular orbital theory. Now we will

5:22

take the example of a nitrogen molecule.

5:25

As we know the atomic number of nitrogen

5:27

is 7. From the electronic configuration

5:29

of nitrogen, we can see that in this

5:31

case, first of all, the 2s orbital of

5:33

the first nitrogen atom should overlap

5:36

with the 2s orbital of the second

5:37

nitrogen atom and will form two

5:39

molecular orbitals of nitrogen. And as

5:41

mentioned earlier, electrons will be

5:43

placed in them. But here we need to

5:45

deeply understand how 2 p orbitals will

5:47

overlap and how electrons will be placed

5:49

in them. First of all, remember that 3 2

5:52

p orbitals of one nitrogen will overlap

5:54

with 32 p orbitals of the second

5:56

nitrogen. It means that a total of six

5:58

orbitals are intermixing in this case.

6:01

So according to the postulate, six

6:03

molecular orbitals should be formed. But

6:05

we need to understand that half will

6:06

have lower energy and half will have

6:08

higher energy than their parent

6:10

orbitals. This means that out of six

6:12

molecular orbitals, three will be

6:13

bonding molecular orbitals and three

6:16

will be anti-bonding molecular orbitals.

6:18

In the next step, we need to place

6:19

electrons of 2 p orbitals into molecular

6:22

orbitals that are being formed. In this

6:24

case, as we can see, there are a total

6:26

of six electrons present in atomic

6:28

orbitals. So, we have to place them in

6:29

molecular orbitals. All these six

6:31

electrons will be placed in bonding

6:33

molecular orbitals and no electron will

6:35

go towards anti-bonding molecular

6:37

orbitals. Now, if we move towards the

6:39

bond order of this molecule again, we

6:42

need to apply the formula which shows

6:43

that there are six electrons in bonding

6:45

molecular orbitals and no electrons are

6:47

present in anti-bonding molecular

6:49

orbitals. So it will be 6 subtracting 0

6:52

and divided by two and its answer will

6:54

be three. This shows that the bond order

6:56

of nitrogen is three and it will form

6:58

three bonds. Now if we look at its

7:00

magnetic behavior as we can see all

7:02

electrons in molecular orbitals are

7:04

paired and no unpaired electrons are

7:06

present here. So we can say that

7:08

nitrogen is diiamagnetic in nature. Now

7:11

we'll discuss how to write the relative

7:12

energy order for molecular orbitals.

7:14

Keep in mind that molecular orbitals

7:16

formed are different in energy from each

7:18

other. So in order to assign them an

7:20

energy order, we simply need to start

7:22

writing their energy levels in ascending

7:24

order. For example, in the case of

7:26

hydrogen, as mentioned above, sigma 1s

7:28

will have lower energy than sigma star 1

7:31

s. Similarly, if a molecule also has 2 s

7:34

orbitals involved in mixing, we can say

7:36

that the energy of sigma 2s will be

7:38

lower than sigma star 2s. But one thing

7:41

we need to keep in mind is that the

7:42

energy of pi^ 2 py and 2pz will always

7:46

be equal. So by following this simple

7:49

concept we can write the energy order

7:51

for any molecule. Now we will discuss

7:53

how molecular orbital theory explains

7:56

ions such as hydrogen ion, nitrogen ion

7:59

and oxygen ion. First let's start with

8:01

hydrogen ion. As we know a neutral

8:03

hydrogen atom has one electron in its 1

8:06

s orbital. When two hydrogen atoms

8:08

combine their atomic orbitals intermix

8:11

to form molecular orbitals resulting in

8:13

bonding and antib-bonding molecular

8:15

orbitals. Now if we consider hydrogen

8:18

molecular ion we can see that only one

8:20

electron is available. According to the

8:22

offbound principle this electron will be

8:24

placed in the lower energy bonding

8:26

molecular orbital which is sigma 1s.

8:28

Since there is no electron present in

8:30

the anti-bonding molecular orbital which

8:32

is sigma star 1 s. The bond order can be

8:35

found using the formula. So we can see

8:37

bond order will be equal to 1

8:38

subtracting 0 and divided by 2 which

8:41

will be equal to 0.5. Since the bond

8:44

order is not zero, it means that

8:46

hydrogen molecular ion is capable of

8:48

existing as a weakly bonded species but

8:50

it will be less stable than hydrogen

8:52

molecule. Now let's move to nitrogen

8:54

ion. For a neutral nitrogen molecule, we

8:56

know that nitrogen has an atomic number

8:58

of 7. Meaning its electronic

9:00

configuration is 1 s2 2 s2 2 p3. Now

9:04

let's consider nitrogen ion. Since

9:06

nitrogen negative ion has one extra

9:08

electron, it will be placed in the next

9:10

available molecular orbital which is a

9:12

pi star 2p orbital. Now the bond order

9:15

will also change. Bond order will be

9:17

equal to 8 subtracting 3 and divided by

9:20

2 which will be equal to 2.5. This means

9:22

that when an extra electron is added the

9:25

bond order decreases making nitrogen

9:27

negative ion less stable than a neutral

9:29

nitrogen molecule. Now we will discuss

9:32

oxygen ion. Molecular orbital

9:34

explanation for O negative ion. Now if

9:37

we consider oxygen negative ion, it has

9:40

one extra electron which will enter the

9:42

pi star 2p orbital. This changes the

9:44

bond order as follows. Bond order will

9:46

be equal to 8 subtracting 5 and divided

9:49

by 2 which will be equal to 1.5. This

9:52

means that oxygen negative ion has a

9:54

lower bond order than a neutral oxygen

9:56

molecule making it less stable and

9:58

weaker in bonding strength. Effect of

10:00

charge on bond order and stability. From

10:02

these examples, we can conclude that

10:04

adding an electron as in nitrogen

10:07

negative ion and oxygen negative ion

10:10

decreases bond order making the molecule

10:12

weaker. Removing an electron as in

10:14

hydrogen molecular ion reduces bond

10:17

order but does not completely eliminate

10:19

bonding. More charge generally results

10:21

in a weaker molecular bond due to

10:23

increased electron repulsion in

10:25

antib-bonding orbitals. Now moving

10:27

towards limitations of molecular

10:29

orbitals theory. It has several

10:30

important limitations. Number one, no

10:33

clear molecular shape. It does not

10:34

explain the exact shapes of molecules

10:36

unlike VR theory. Number two, complex

10:40

mathematical calculations. The theory

10:42

relies on advanced math making it

10:44

difficult to apply. Number three, fails

10:46

for some molecules. It does not

10:48

correctly predict bonding in certain

10:50

molecules such as oxygen where

10:51

experimental results show differences in

10:53

magnetic properties. Number four, weak

10:56

explanation of bond strength. It does

10:58

not always explain why some bonds are

10:59

stronger or weaker in certain molecules.

11:02

Number five, contradictions with other

11:04

theories. It sometimes disagrees with

11:06

valance bond theory, which explains

11:08

bonding in a different way.

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