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IUPAC Nomenclature Rules Explained In 10 Minutes

10:13EnglishTranscribed Jul 26, 2026
0:00

First, let's start with nomenclature of

0:02

alkanes. Rule one, how to identify the

0:04

longest parent chain. The first step is

0:06

to find the longest continuous chain of

0:08

carbon atoms. Keep in mind that it is

0:10

not necessary that the chain should be

0:12

straight or linear. Let's understand it

0:13

with some examples. Look at this

0:15

structure. If we consider the straight

0:17

chain, it has five carbons. But if we

0:19

consider the carbons that are not

0:20

involved in the linear structure, then

0:22

it has six carbons. So, the correct way

0:24

is to select this longest possible chain

0:26

which has the maximum possible number of

0:28

carbons in it. Rule two, how to number

0:30

the parent chain. If the parent chain

0:32

has no branch, the numbering can start

0:34

from any side. To understand it, take

0:36

this structure. It has five carbons and

0:38

all carbons are present in the parent

0:40

chain. It means it has no branch. So,

0:42

its name will be npentane and we can

0:45

start numbering from any side. Keep in

0:46

mind that here N refers to the structure

0:48

having no branch. But if the parent

0:50

chain has a branch, then numbering will

0:52

start from the side that gives the least

0:54

number to the branch attached. Let's

0:56

take the following structure as an

0:57

example. If we start numbering from

0:59

right to left, the substituent or branch

1:01

is present at the fourth carbon. But if

1:03

we consider it from left to right, the

1:04

branch is attached at the second carbon.

1:06

So according to the rule, numbering

1:08

should start from left to right as it

1:10

gives the least number to the branch

1:11

attached. Rule three, how to name the

1:14

substituents. The substituents are named

1:16

based on the number of carbons they

1:17

have. For example, if the branch has one

1:20

carbon, it is called methyl. And if it

1:21

has two carbons, it will be called

1:23

ethel. Actually, it's very easy to name

1:25

a branch. just change the name ending in

1:27

a ne to Y L. For example, as we know one

1:30

carbon is called methane and if one

1:32

carbon is present as a branch then its

1:34

name will become methyl. Similarly, if

1:37

two carbons are present as a branch or

1:39

substituent, then the name ethane will

1:40

change to ethl. Let's take these two

1:42

structures as an example. Since the

1:44

first structure has one carbon as a

1:46

branch, it will be called methyl and the

1:48

second structure has two carbons. So,

1:50

the name of the branch will be ethyl.

1:52

Rule four. How to write the complete

1:54

name of a structure. First write the

1:55

number of the carbon on which the

1:57

substituent or branch is attached. After

1:59

that write the name of the branch

2:01

attached and at the end write the total

2:03

number of carbons present in the parent

2:04

chain. To understand this let's take the

2:06

following structure as an example. It

2:08

has a methyl group as a substituent.

2:10

Since from both sides the number of the

2:12

substituent will be the same which is

2:14

two. We can assign the number from

2:15

either side. The total number of carbons

2:17

in the parent chain is three. So

2:19

according to the rule the name of this

2:21

structure will be two methyl propane.

2:23

Let's take another example to understand

2:25

it more deeply. In this structure, the

2:27

branch attached contains two carbons, so

2:29

it will be called ethel. And the total

2:31

number of carbons in the parent chain is

2:33

seven. Numbering will start from the

2:34

right side because it gives the least

2:36

number to the branch attached. By

2:38

following all the above mentioned rules,

2:40

the name of the structure will be two

2:42

ethyl heptine. Rule five, how to name

2:44

multiple substituents. First, let's

2:46

focus on what to do if the same

2:48

substituent is present on more than one

2:50

carbon. In this case, we name the

2:51

substituents by using prefixes such as

2:54

di tetra and so on. One thing you need

2:56

to keep in mind is that we have to write

2:58

the number of each carbon that contains

3:00

a branch or substituent. Let's take this

3:02

structure as an example. It has two

3:04

methyl groups as branches and they are

3:06

present at positions 2 and four. So in

3:08

order to name this structure, first we

3:10

have to write the number of each carbon

3:12

that contains a branch. The overall name

3:14

will be two four dimethylhexane. But

3:16

what if the branches are different from

3:18

each other? For example, if one branch

3:20

is methyl and the other is ethl. In this

3:22

case, we need to follow alphabetical

3:24

order. Since E comes before M, we have

3:26

to write Ethel first and after that we

3:28

can write methyl. Let's take the

3:30

following example to make it clear. The

3:31

name of the structure will be two ethyl

3:33

3methylhexane. Rule six. How to name

3:36

cyclic alkanes? It is very easy to

3:38

assign names to cyclic alkanes. If the

3:40

structure has a ring, we need to add the

3:42

prefix cylo before the parent chain

3:44

name. For example, this structure has

3:46

four carbons and they are in ring form.

3:48

So its name will be cyclloutane. Now

3:51

let's move towards the nomenclature of

3:52

alkenes. Rule one, select the longest

3:55

possible chain that contains the double

3:57

bond. Keep in mind if you select a chain

3:59

that has the maximum number of carbons

4:00

but does not contain the double bond, it

4:02

will be incorrect. The reason is that

4:04

here we need to prefer the double bond

4:06

over the single bond and the chain must

4:08

include the double bond. To understand

4:10

this deeply, let's take the following

4:11

example. This structure has six carbons

4:14

in a straight chain but the double bond

4:15

is not present in it. However, if we

4:17

select the chain that contains the

4:19

double bond, it has four carbons. So,

4:21

according to the rule, the parent chain

4:23

with four carbons is correct because it

4:25

also contains the double bond. Rule two,

4:27

how to number the parent chain and

4:28

branches. If the parent chain contains a

4:30

double bond, the numbering should be

4:32

done in such a way that it gives the

4:34

least number to the double bond. Keep in

4:36

mind here we should not prioritize the

4:38

branch for numbering. Since the parent

4:39

chain contains a double bond, we should

4:41

prefer to give the least number to the

4:43

double bond rather than the branch

4:44

attached. Let's take the following

4:46

example to understand this. Since the

4:48

double bond is present on the second

4:49

carbon, numbering will start from left

4:51

to right as it gives the least number to

4:53

the double bond. Rule three, how to name

4:55

the parent chain having a double bond.

4:57

If the parent chain does not contain any

4:59

branches or substituents, the name

5:01

should be given in such a way that the

5:02

position of the carbon containing the

5:04

double bond is mentioned first. After

5:06

that, the total number of carbons in the

5:08

parent chain is indicated ending the

5:10

name with E and E. Let's make this clear

5:12

with this structure. Since the parent

5:14

chain has five carbons and the double

5:16

bond is present at the second carbon,

5:18

its name will be two pentine. Rule four,

5:20

how to name a branched chain structure

5:22

having a double bond. One thing to keep

5:24

in mind is that while writing the name

5:26

of compounds, whether they contain a

5:27

double or single bond, we need to

5:29

mention and write the substituent or

5:31

branch at the start of the name. For

5:32

example, let's take this structure to

5:34

understand this. Since a methyl group is

5:36

present on the third carbon and the

5:38

double bond is present on the second

5:40

carbon, the name of this compound will

5:41

be threemethyl 2 butine. Rule five, how

5:44

to name multiple branches in a double

5:46

bond. If the parent chain has more than

5:48

one similar branch, we need to use

5:50

prefixes such as dri and tetra. However,

5:53

if it contains different branches, we

5:55

need to follow alphabetical order just

5:57

like in the case of alkanes. Look at

5:59

this structure. It has a double bond at

6:00

the first carbon, two methyl groups

6:02

attached at the third carbon, and an

6:04

ethyl group on the fourth carbon. Since

6:06

the substituents are different, we need

6:07

to follow the alphabetical rule. Its

6:09

name will be four ethyl 333

6:11

dimethylhexene. Rule six, how to name

6:14

more than one double bond in a

6:15

structure. If there is more than one

6:17

double bond, use prefixes like dyen for

6:20

two double bonds, try ena for three, and

6:22

so on. Don't forget to number the

6:24

positions of all the double bonds. Have

6:26

a look at this structure. It has two

6:28

double bonds at carbons 1 and three. So

6:30

its name should be one. Three but dyene.

6:33

Rule seven. How to name cis and trans

6:35

isomers having double bonds. To

6:37

understand this, let's take the example

6:39

of two butin. If both methyl groups are

6:41

present on the same side of the double

6:42

bond, it will be called cis 2butine. But

6:45

if both methyl groups are present on

6:47

opposite sides of the double bond, it

6:48

will be called transbboutine. And now

6:51

finally let's move towards the

6:52

nomenclature of alkyes. Rule one. Select

6:55

the longest possible chain that contains

6:57

the triple bond. When naming alkyes, the

6:59

first step is to identify the longest

7:00

continuous carbon chain that includes

7:02

the triple bond. Even if another chain

7:04

has more carbons but does not include

7:05

the triple bond, it would not be

7:07

considered the correct parent chain.

7:08

This is because the triple bond is given

7:10

priority over single bonds when

7:12

selecting the main chain. Let's take an

7:14

example to understand this better.

7:16

Imagine we have a structure with six

7:18

carbons in a straight chain, but the

7:19

triple bond is not part of it. If we

7:21

select the chain containing the triple

7:22

bond, it has five carbons. According to

7:25

this rule, the five carbons chain is the

7:27

correct parent chain because it includes

7:28

the triple bond. Rule two, how to number

7:31

the parent chain and branches. Once the

7:33

parent chain is selected, the next step

7:35

is to assign numbers to the carbons in

7:36

the chain. The numbering should be done

7:38

in such a way that the triple bond gets

7:40

the lowest possible number. It's

7:41

important to note that the location of

7:43

the triple bond is more important than

7:44

the position of any branches or

7:46

substituents when assigning numbers. For

7:48

instance, if the triple bond is on the

7:50

second carbon, numbering should start

7:52

from the end of the chain closest to the

7:53

triple bond. Even if it means the branch

7:55

gets a higher number. Let's look at an

7:57

example to clarify. If the triple bond

7:59

is on the second carbon and the branch

8:00

is further down the chain, numbering

8:02

will start from the end nearest to the

8:04

triple bond to give it the smallest

8:05

possible number. Rule three, how to name

8:08

the parent chain having a triple bond.

8:10

If the parent chain does not contain any

8:12

substituents or branches, the name

8:13

should reflect the position of the

8:15

triple bond followed by the total number

8:17

of carbons in the chain and ending with

8:18

Y ne to indicate the presence of a

8:21

triple bond. For example, consider a

8:23

structure with five carbons in the main

8:25

chain and a triple bond present at the

8:26

second carbon. The name of this compound

8:28

will be two pentine. Rule four. How to

8:31

name a branched chain structure having a

8:33

triple bond. When a triple bond is

8:35

present along with branches, the

8:37

position and name of the branches or

8:38

substituents must be mentioned at the

8:40

beginning of the compound's name. It's

8:42

essential to prioritize the triple bond

8:44

when numbering, ensuring that it gets

8:46

the smallest possible number. Let's take

8:48

an example. If a methyl group is

8:49

attached to the third carbon and a

8:51

triple bond is located on the second

8:53

carbon, the name of this compound will

8:54

be threemethyl 2 butine. Rule five. How

8:57

to name multiple branches in a chain

8:59

with a triple bond. If the parent chain

9:01

has identical branches, prefixes like

9:03

die, try and tetra are used to indicate

9:06

the number of branches. If there are

9:08

different types of branches, they are

9:09

arranged in alphabetical order when

9:11

naming the compound. Consider this

9:13

structure. The parent chain has a triple

9:15

bond on the first carbon, two methyl

9:17

groups on the third carbon, and an ethyl

9:19

group on the fourth carbon. Since the

9:20

branches are different, we follow the

9:22

alphabetical order. The name of this

9:24

compound will be four ethyl 33 dmethyl

9:27

1hexene. Rule six, how to name compounds

9:30

with more than one triple bond. If a

9:32

compound has multiple triple bonds,

9:34

prefixes like diion for two triple

9:36

bonds, triion for three triple bonds and

9:38

so on are used. Additionally, the

9:40

positions of all triple bonds must be

9:42

indicated in the name. There are some

9:44

special cases when both double and

9:46

triple bond are present in the parent

9:48

chain. Then we should prefer the double

9:49

bond and numbering will start from that

9:51

side which gives least number to double

9:53

bond and also need to prefer double bond

9:55

in naming also. Let's take the following

9:57

structure to make it clear. It has

9:58

double bond and second carbon and triple

10:00

bond at fifth carbon. So its name will

10:02

be two hexene 5 ion. I hope this video

10:05

was helpful for you. If you still have

10:06

any confusion, let me know if it

10:08

comments. See you next in another

10:09

amazing explainer video.

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