All of Alkanes Explained in 10 Minutes
Alkanes are saturated class of
hydrocarbons which means that in this
case a single bond is present between
carbon atoms and we need to remember
that actually saturated compounds are
those compounds which only contain a
single bond present in them. First of
all we need to understand the general
formula of alkanes and it is CNH2N
plus2. Keep in mind here N represents
the total number of carbon atoms present
in alkan. To understand it deeply let's
apply this formula to a few examples. If
the number of carbon atoms in alkan is
equal to 1, it means that by applying
the formula we will get methane with the
formula CH4 and also you need to keep in
mind that methane is the simplest alkan.
Now if we apply this formula when n is
equal to 2, we will get C2H6
which is called ethane. Keep in mind
that by applying the same formula for
any number of carbon atoms, we can find
out how many hydrogens will be present
in each case. Now let's understand why
alkanes are also called paraffins. Here
we need to remember that paraffins is a
Latin word which is actually a
combination of two words and they are
pum meaning little and aphinis meaning
affinity which tells us that alkanes are
actually very less reactive. The main
reasons for the less reactivity of
alkanes are due to the non-reactivity of
the sigma bond present in alkanes. Now
let's move towards the nomenclature of
alkanes. To understand it deeply first
we need to learn some important rules.
The first and most important rule is
that we have to select the longest
possible carbon chain which will give
the parent name to the alkanes. To
understand the first rule, let's have a
look at the following structure. Since
the longest possible chain has five
carbons, we need to select it. Now, if
we move towards the second rule, it says
that if the parent chain has any branch
or substituent present on it, then
numbering will start from that side,
which gives the least number to the
branch attached. To understand it, let's
look at the following structure. In this
case, since the methyl group is present
on the second carbon from the left side,
we have to start numbering from left to
right and its name will be two methyl
pentane. Moving towards the third rule,
if branches are identical, we should use
prefixes such as try, tetra and so on.
But keep in mind if branches present on
the parent chain are different, we need
to follow alphabetical order. Which
means that if the parent chain has both
methyl and ethyl groups present as
branches or substituents then in this
case since ethel comes alphabetically
first before methyl we will write
ethylmethyl rather than methyl ethel
which follows alphabetical order. Now we
should move towards the preparation of
alkanes. First we will discuss the
preparation of alkanes from alkenes and
alkynes. Keep in mind that alkanes can
be prepared from the hydrogenation of
unsaturated hydrocarbons such as alkenes
and alkyes. Actually hydrogenation
refers to the addition of hydrogen and
in this case hydrogenation is done in
the presence of catalysts such as nickel
and platinum. If we look at the reaction
for the formation of alkanes by
hydrogenation of unsaturated
hydrocarbons. In this case ethine will
react with one mole of hydrogen which
will result in the breaking of the
carbonarbon double bond and will lead to
the formation of ethane. Now we should
move towards the warts reaction for the
preparation of alkanes. We need to
understand that this method is used to
prepare higher alkanes. In this case,
alkalhalides react with sodium and dry
ether to form alkanes. If we look at the
reaction, in this case, two molar
concentrations of methyl bromide will
react with two molar concentrations of
sodium to form one molar concentration
of ethane and two molar concentrations
of sodium bromide. Keep in mind that we
can also prepare alkanes from the
decarboxilation of caroxyic acids. In
this case, first we need to understand
that actually decarboxilation means the
removal of the caroxile group. And if we
remove the caroxile group, it will
result in the formation of alkan. Keep
in mind that this reaction happens when
the sodium salt of caroxyic acids reacts
with sodaline. If we look at the
balanced chemical reaction for the
formation of alkanes. In this case, one
mole of sodium acetate will react with
one mole of sodium to form one molar
concentration of methane and sodium
carbonate. Now we should move towards
reactions of alkanes. But keep in mind
that although alkanes are chemically
inert, they can still undergo some
reactions such as thermal or catalytic
reactions and substitution reactions. In
a complete combustion reaction of
methane, it will produce carbon dioxide
and two molar concentrations of water
molecules. But if an incomplete
combustion reaction takes place, it will
result in the formation of carbon
monoxide and water molecules. Now if we
move towards the catalytic oxidation of
methane it can change into formaldahhide
and formic acid. You need to keep in
mind that catalytic oxidation means the
addition of oxygen in the presence of a
suitable catalyst. During this reaction
in the first step methane will react
with a water molecule to form methanol.
Next in the second step methanol will be
converted into formaldahhide and finally
the oxidation of formaldahhide will
change it into formic acid. Now let's
move towards a very important reaction
of alkanes which is called the h
hallogenation of alcanes. This reaction
takes place in the presence of sunlight
and it follows a free radical mechanism.
Keep in mind that a free radical refers
to a highly reactive species with an
unpaired electron. Actually the free
radical mechanism takes place in three
steps which are initiation, propagation
and termination. In the first step
during initiation the formation of
radicals takes place. During the second
step propagation takes place. Remember
that propagation means the growth of
free radicals. In this step, radicals
will keep on growing during several
reactions and will result in the
formation of many valuable products. In
the last step, two radicals will react
with each other to form a stable
product. Here we need to understand that
termination refers to the ending or
termination of radicals. If we look at
the mechanism of the halogenation
reaction in this case during the
initiation process, a chlorine molecule
which means Cl2 will break down into two
chlorine radicals. In the second step
which is called propagation, these
chlorine radicals produced in the first
step will react with methane to produce
many valuable products by the successive
replacement of hydrogen atoms with
halogen. And after that finally in the
third step which is called termination
here a methyl radical will react with a
chlorine radical to produce methyl
chloride. As we can see that in this
case in the products no radical is
formed. So from here we can say that
during the halogenation process in the
third step radicals are terminated. Now
let's move towards isomeism phenomenon
in alkanes. Actually isomeism in alcanes
occurs when compounds have the same
molecular formula but different
structures. This means they contain the
same number of carbon and hydrogen atoms
but their atoms are arranged in
different ways. This type of isomeism in
alkanes is called structural isomeism
specifically chain isomeism. It happens
when the arrangement of carbon atoms in
the chain changes leading to different
physical and chemical properties. Now
let's understand chain isomeism in
alkanes. Alkanes can exist as straight
chain or branched chain isomers.
Straight chain isomers have all carbon
atoms connected in a continuous line
without any branches. And branched chain
isomers have at least one carbon atom
attached to the main chain as a side
group forming a branch. Even though
these isomers have the same molecular
formula, their properties such as
boiling points and densities can be
different because of their structural
differences. To understand it deeply,
let's take the example for the possible
isomers of butane. Remember that butane
is an example of an alkan that shows
chain isomeism. It has two isomers and
they are straight chain and branch
chain. In straight chain structure, all
four carbon atoms are connected in a
straight line. This isomer has a higher
boiling point than its branched
counterpart because its molecules can
pack closely together leading to
stronger intermolecular forces. But if
we look at the branched structure, three
carbon atoms form the main chain and the
fourth carbon is attached as a branch to
the second carbon. Because of its
branched structure, isobutane has a
lower boiling point than nb butane since
its molecules cannot pack as tightly as
straight chain molecules. One important
point we need to remember that as the
number of carbon atoms and alkanes
increases, the number of possible
isomers also increases. This is because
there are more ways to arrange the
carbon atoms in different chains. For
example, pentane has three isomers,
hexane has five isomers, and heptine has
nine isomers. This proves that the
number of possible isomers increases
rapidly with more carbon atoms, making
it more difficult to name and
differentiate them. Now, let's
understand physical properties of
alkanes. We need to understand that
alkanes have specific physical
properties that depend on their
molecular size and structure. These
properties include boiling points,
melting points, and solubility. Since
alkanes are non-polar molecules, their
behavior is mainly influenced by weak
London dispersion forces which are
temporary attractions between molecules.
First, let's have a look at melting and
boiling point. The boiling and melting
points of alkanes increase as the number
of carbon atoms increases. This happens
because larger alkanes have more
electrons and a greater surface area
leading to stronger London dispersion
forces between molecules. More energy is
needed to break these forces which
results in higher boiling and melting
points. For example, methane is a gas at
room temperature, but octane is a liquid
because it has stronger intermolecular
forces. Keep in mind that the structure
of an alkan also affects its boiling
point. Branched chain alkanes have lower
boiling points than straight chain
alkanes of the same molecular formula.
This is because branched molecules are
more compact and have less surface area
for intermolecular forces to act, making
it easier for them to evaporate. For
example, npentane has a higher boiling
point than its branched isomer
isopentane. Now let's discuss solubility
of alkanes. Alkanes are insoluble in
water because they are non-polar while
water is a polar solvent. The principle
like dissolves like explains why
non-polar substances do not mix with
polar substances. Water molecules
attract each other strongly through
hydrogen bonding and since alkanes
cannot form these bonds, they do not
dissolve in water. However, alkanes are
soluble in non-polar solvents like
benzene, ether, and chloroform. This is
because non-polar solvents have similar
weak intermolecular forces allowing
alkanes to dissolve easily. Now, let's
discuss some important use of alkanes.
Alcanes like methane, propane, and
butane are used as fuels in homes,
industries, and vehicles. Methane is
used in natural gas for cooking and
heating. Higher alkanes such as paraffin
wax are used in making candles,
polishes, and waterproof coatings. They
also serve as lubricants in machinery
and engines to reduce friction. Alkanes
like hexane and heptine are used as
solvents in industries for extracting
oils, cleaning, and dissolving non-polar
substances. They are also used in paints
and coatings. Alkanes are also the main
components of crude oil and are refined
into different fuels like petrol,
diesel, and kerosene. Alkanes also serve
as raw materials for making various
chemicals including alcohols, plastics,
and detergents. They undergo chemical
reactions like halogenation to produce
useful compounds for different
industries.
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