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All of Alkanes Explained in 10 Minutes

10:53EnglishTranscribed Jul 26, 2026
0:00

Alkanes are saturated class of

0:01

hydrocarbons which means that in this

0:03

case a single bond is present between

0:05

carbon atoms and we need to remember

0:07

that actually saturated compounds are

0:10

those compounds which only contain a

0:12

single bond present in them. First of

0:14

all we need to understand the general

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formula of alkanes and it is CNH2N

0:18

plus2. Keep in mind here N represents

0:21

the total number of carbon atoms present

0:23

in alkan. To understand it deeply let's

0:26

apply this formula to a few examples. If

0:28

the number of carbon atoms in alkan is

0:30

equal to 1, it means that by applying

0:32

the formula we will get methane with the

0:34

formula CH4 and also you need to keep in

0:36

mind that methane is the simplest alkan.

0:39

Now if we apply this formula when n is

0:41

equal to 2, we will get C2H6

0:44

which is called ethane. Keep in mind

0:46

that by applying the same formula for

0:48

any number of carbon atoms, we can find

0:50

out how many hydrogens will be present

0:51

in each case. Now let's understand why

0:54

alkanes are also called paraffins. Here

0:56

we need to remember that paraffins is a

0:58

Latin word which is actually a

1:00

combination of two words and they are

1:01

pum meaning little and aphinis meaning

1:04

affinity which tells us that alkanes are

1:06

actually very less reactive. The main

1:09

reasons for the less reactivity of

1:10

alkanes are due to the non-reactivity of

1:13

the sigma bond present in alkanes. Now

1:15

let's move towards the nomenclature of

1:17

alkanes. To understand it deeply first

1:20

we need to learn some important rules.

1:22

The first and most important rule is

1:24

that we have to select the longest

1:25

possible carbon chain which will give

1:27

the parent name to the alkanes. To

1:29

understand the first rule, let's have a

1:30

look at the following structure. Since

1:32

the longest possible chain has five

1:34

carbons, we need to select it. Now, if

1:36

we move towards the second rule, it says

1:38

that if the parent chain has any branch

1:40

or substituent present on it, then

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numbering will start from that side,

1:43

which gives the least number to the

1:45

branch attached. To understand it, let's

1:47

look at the following structure. In this

1:49

case, since the methyl group is present

1:50

on the second carbon from the left side,

1:52

we have to start numbering from left to

1:54

right and its name will be two methyl

1:56

pentane. Moving towards the third rule,

1:58

if branches are identical, we should use

2:00

prefixes such as try, tetra and so on.

2:04

But keep in mind if branches present on

2:06

the parent chain are different, we need

2:07

to follow alphabetical order. Which

2:09

means that if the parent chain has both

2:11

methyl and ethyl groups present as

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branches or substituents then in this

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case since ethel comes alphabetically

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first before methyl we will write

2:19

ethylmethyl rather than methyl ethel

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which follows alphabetical order. Now we

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should move towards the preparation of

2:25

alkanes. First we will discuss the

2:27

preparation of alkanes from alkenes and

2:29

alkynes. Keep in mind that alkanes can

2:31

be prepared from the hydrogenation of

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unsaturated hydrocarbons such as alkenes

2:35

and alkyes. Actually hydrogenation

2:38

refers to the addition of hydrogen and

2:40

in this case hydrogenation is done in

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the presence of catalysts such as nickel

2:44

and platinum. If we look at the reaction

2:46

for the formation of alkanes by

2:48

hydrogenation of unsaturated

2:50

hydrocarbons. In this case ethine will

2:53

react with one mole of hydrogen which

2:55

will result in the breaking of the

2:56

carbonarbon double bond and will lead to

2:58

the formation of ethane. Now we should

3:00

move towards the warts reaction for the

3:02

preparation of alkanes. We need to

3:04

understand that this method is used to

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prepare higher alkanes. In this case,

3:08

alkalhalides react with sodium and dry

3:10

ether to form alkanes. If we look at the

3:13

reaction, in this case, two molar

3:15

concentrations of methyl bromide will

3:17

react with two molar concentrations of

3:19

sodium to form one molar concentration

3:21

of ethane and two molar concentrations

3:23

of sodium bromide. Keep in mind that we

3:25

can also prepare alkanes from the

3:27

decarboxilation of caroxyic acids. In

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this case, first we need to understand

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that actually decarboxilation means the

3:34

removal of the caroxile group. And if we

3:36

remove the caroxile group, it will

3:38

result in the formation of alkan. Keep

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in mind that this reaction happens when

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the sodium salt of caroxyic acids reacts

3:45

with sodaline. If we look at the

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balanced chemical reaction for the

3:48

formation of alkanes. In this case, one

3:50

mole of sodium acetate will react with

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one mole of sodium to form one molar

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concentration of methane and sodium

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carbonate. Now we should move towards

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reactions of alkanes. But keep in mind

4:00

that although alkanes are chemically

4:02

inert, they can still undergo some

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reactions such as thermal or catalytic

4:06

reactions and substitution reactions. In

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a complete combustion reaction of

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methane, it will produce carbon dioxide

4:12

and two molar concentrations of water

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molecules. But if an incomplete

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combustion reaction takes place, it will

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result in the formation of carbon

4:20

monoxide and water molecules. Now if we

4:23

move towards the catalytic oxidation of

4:25

methane it can change into formaldahhide

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and formic acid. You need to keep in

4:29

mind that catalytic oxidation means the

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addition of oxygen in the presence of a

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suitable catalyst. During this reaction

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in the first step methane will react

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with a water molecule to form methanol.

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Next in the second step methanol will be

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converted into formaldahhide and finally

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the oxidation of formaldahhide will

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change it into formic acid. Now let's

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move towards a very important reaction

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of alkanes which is called the h

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hallogenation of alcanes. This reaction

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takes place in the presence of sunlight

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and it follows a free radical mechanism.

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Keep in mind that a free radical refers

5:00

to a highly reactive species with an

5:02

unpaired electron. Actually the free

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radical mechanism takes place in three

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steps which are initiation, propagation

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and termination. In the first step

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during initiation the formation of

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radicals takes place. During the second

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step propagation takes place. Remember

5:17

that propagation means the growth of

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free radicals. In this step, radicals

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will keep on growing during several

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reactions and will result in the

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formation of many valuable products. In

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the last step, two radicals will react

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with each other to form a stable

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product. Here we need to understand that

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termination refers to the ending or

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termination of radicals. If we look at

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the mechanism of the halogenation

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reaction in this case during the

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initiation process, a chlorine molecule

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which means Cl2 will break down into two

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chlorine radicals. In the second step

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which is called propagation, these

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chlorine radicals produced in the first

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step will react with methane to produce

5:52

many valuable products by the successive

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replacement of hydrogen atoms with

5:55

halogen. And after that finally in the

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third step which is called termination

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here a methyl radical will react with a

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chlorine radical to produce methyl

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chloride. As we can see that in this

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case in the products no radical is

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formed. So from here we can say that

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during the halogenation process in the

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third step radicals are terminated. Now

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let's move towards isomeism phenomenon

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in alkanes. Actually isomeism in alcanes

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occurs when compounds have the same

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molecular formula but different

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structures. This means they contain the

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same number of carbon and hydrogen atoms

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but their atoms are arranged in

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different ways. This type of isomeism in

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alkanes is called structural isomeism

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specifically chain isomeism. It happens

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when the arrangement of carbon atoms in

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the chain changes leading to different

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physical and chemical properties. Now

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let's understand chain isomeism in

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alkanes. Alkanes can exist as straight

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chain or branched chain isomers.

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Straight chain isomers have all carbon

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atoms connected in a continuous line

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without any branches. And branched chain

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isomers have at least one carbon atom

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attached to the main chain as a side

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group forming a branch. Even though

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these isomers have the same molecular

7:01

formula, their properties such as

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boiling points and densities can be

7:04

different because of their structural

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differences. To understand it deeply,

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let's take the example for the possible

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isomers of butane. Remember that butane

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is an example of an alkan that shows

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chain isomeism. It has two isomers and

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they are straight chain and branch

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chain. In straight chain structure, all

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four carbon atoms are connected in a

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straight line. This isomer has a higher

7:24

boiling point than its branched

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counterpart because its molecules can

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pack closely together leading to

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stronger intermolecular forces. But if

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we look at the branched structure, three

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carbon atoms form the main chain and the

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fourth carbon is attached as a branch to

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the second carbon. Because of its

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branched structure, isobutane has a

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lower boiling point than nb butane since

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its molecules cannot pack as tightly as

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straight chain molecules. One important

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point we need to remember that as the

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number of carbon atoms and alkanes

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increases, the number of possible

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isomers also increases. This is because

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there are more ways to arrange the

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carbon atoms in different chains. For

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example, pentane has three isomers,

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hexane has five isomers, and heptine has

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nine isomers. This proves that the

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number of possible isomers increases

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rapidly with more carbon atoms, making

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it more difficult to name and

8:12

differentiate them. Now, let's

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understand physical properties of

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alkanes. We need to understand that

8:17

alkanes have specific physical

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properties that depend on their

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molecular size and structure. These

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properties include boiling points,

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melting points, and solubility. Since

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alkanes are non-polar molecules, their

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behavior is mainly influenced by weak

8:30

London dispersion forces which are

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temporary attractions between molecules.

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First, let's have a look at melting and

8:36

boiling point. The boiling and melting

8:38

points of alkanes increase as the number

8:40

of carbon atoms increases. This happens

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because larger alkanes have more

8:44

electrons and a greater surface area

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leading to stronger London dispersion

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forces between molecules. More energy is

8:51

needed to break these forces which

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results in higher boiling and melting

8:54

points. For example, methane is a gas at

8:57

room temperature, but octane is a liquid

8:59

because it has stronger intermolecular

9:01

forces. Keep in mind that the structure

9:03

of an alkan also affects its boiling

9:05

point. Branched chain alkanes have lower

9:08

boiling points than straight chain

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alkanes of the same molecular formula.

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This is because branched molecules are

9:13

more compact and have less surface area

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for intermolecular forces to act, making

9:18

it easier for them to evaporate. For

9:20

example, npentane has a higher boiling

9:22

point than its branched isomer

9:24

isopentane. Now let's discuss solubility

9:27

of alkanes. Alkanes are insoluble in

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water because they are non-polar while

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water is a polar solvent. The principle

9:34

like dissolves like explains why

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non-polar substances do not mix with

9:38

polar substances. Water molecules

9:40

attract each other strongly through

9:42

hydrogen bonding and since alkanes

9:44

cannot form these bonds, they do not

9:46

dissolve in water. However, alkanes are

9:48

soluble in non-polar solvents like

9:51

benzene, ether, and chloroform. This is

9:53

because non-polar solvents have similar

9:55

weak intermolecular forces allowing

9:57

alkanes to dissolve easily. Now, let's

9:59

discuss some important use of alkanes.

10:02

Alcanes like methane, propane, and

10:04

butane are used as fuels in homes,

10:06

industries, and vehicles. Methane is

10:08

used in natural gas for cooking and

10:10

heating. Higher alkanes such as paraffin

10:13

wax are used in making candles,

10:15

polishes, and waterproof coatings. They

10:17

also serve as lubricants in machinery

10:19

and engines to reduce friction. Alkanes

10:21

like hexane and heptine are used as

10:23

solvents in industries for extracting

10:25

oils, cleaning, and dissolving non-polar

10:28

substances. They are also used in paints

10:30

and coatings. Alkanes are also the main

10:32

components of crude oil and are refined

10:34

into different fuels like petrol,

10:36

diesel, and kerosene. Alkanes also serve

10:39

as raw materials for making various

10:41

chemicals including alcohols, plastics,

10:43

and detergents. They undergo chemical

10:45

reactions like halogenation to produce

10:47

useful compounds for different

10:49

industries.

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